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(16/625)=(5/2)^3x+2
We move all terms to the left:
(16/625)-((5/2)^3x+2)=0
Domain of the equation: 2)^3x+2)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-((+5/2)^3x+2)+(+16/625)=0
We get rid of parentheses
-((+5/2)^3x+2)+16/625=0
We calculate fractions
()/2^3x+2)*625)+32x/2^3x+2)*625)=0
We calculate fractions
We do not support expression: x^6
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